1200=1/3x^2

Solution for 1200=1/3x^2 equation:

1200=1/3x^2

We move all terms to the left:

1200-(1/3x^2)=0


Domain of the equation: 3x^2)!=0

x!=0/1

x!=0

x∈R


We get rid of parentheses

-1/3x^2+1200=0

We multiply all the terms by the denominator


1200*3x^2-1=0

Wy multiply elements

3600x^2-1=0

a = 3600; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·3600·(-1)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*3600}=\frac{-120}{7200}
=-1/60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*3600}=\frac{120}{7200}
=1/60
$